> > > > NCERT Solutions for Class 9 Maths Chapter 3 : Coordinate Geometry

# NCERT Solutions for Class 9 Maths Chapter 3 : Coordinate Geometry

Click to rate this post!
[Total: 24 Average: 4.5]

NCERT Maths Solutions Class 9 gives the answers to chapter 3 of the syllabus – Coordinate geometry. Chapter 3 has a total of 3 exercises for the students to solve. You will be studying the concept of the cartesian plane, coordinates of a point in this XY – plane, name, terms, notations, and other terms associated with the coordinate plane. Abscissa and ordinate of points. You will learn to Plot a point in XY – plane and the process of naming it.

NCERT Solutions for Class 9 Maths Chapter 3 by Swiflearn are by far the best and most reliable NCERT Solutions that you can find on the internet. These NCERT Solutions for Class 9 Maths Chapter 3 Coordinate Geometry are designed as per the CBSE Class 9 Maths Syllabus. These NCERT Solutions will surely make your learning convenient & fun. Students can also Download FREE PDF of NCERT Solutions Class 9 Chapter 3.

## NCERT Solutions for Class 9 Maths Chapter 3 Coordinate Geometry : EX 3.1

#### Question 1:How will you describe the position of a table lamp on your study table toanother person?

Solution:

From the above Figure, Consider the lamp on the table as a point.
Consider the table as a plane.
We can conclude that the table is rectangular in shape, when observed from the top.
The table has a short edge and a long edge.
Let us measure the distance of the lamp from the shorter edge and the longer edge.
Let us assume: Distance of the lamp from the shorter edge is 15 cm.
Distance of the lamp from the longer edge, its 25 cm.
Therefore, we can conclude that the position of the lamp on the table can be described in two
ways depending on the order of the axes as (15, 25) or (25, 15).

#### crossing, then we will call this cross-street (2, 5). Using this convention,find:(i) How many cross – streets can be referred to as (4, 3).(ii) How many cross – streets can be referred to as (3, 4).

Solution:
Draw two perpendicular lines as the two main roads of the city that cross each other at the center.
Mark it as N–S and E–W.
Let us take the scale as 1 cm = 200 m.
Draw five streets that are parallel to both the main roads, to get the given below figure.

Street plan is as shown in the figure:
(i) There is only one cross street, which can be referred as (4, 3).
(ii) There is only one cross street, which can be referred as (3, 4).

## NCERT Solutions for Class 9 Maths Chapter 3 Coordinate Geometry : EX 3.2

#### Question1:Write the answer of each of the following questions:(i) What is the name of horizontal and the vertical lines drawn to determinethe position of any point in the Cartesian plane?(ii) What is the name of each part of the plane formed by these two lines?(iii) Write the name of the point where these two lines intersect.

Solution:
(i)
The horizontal line that is drawn to determine the position of any point in the Cartesian plane is called as x-axis.
The vertical line that is drawn to determine the position of any point in the Cartesian plane is called as y-axis.
(ii)
The name of each part of the plane that is formed by x-axis and y-axis is called as quadrant.
(iii)
The point, where the x-axis and the y-axis intersect is called as origin (O).

#### Question 2:See the figure, and write the following:(i) The coordinates of B.(ii) The coordinates of C.(iii) The point identified by the coordinates (–3, –5).(iv) The point identified by the coordinates (2, –4).(v) The abscissa of the point D.(vi) The coordinate of the point H.(vii) The coordinates of the point L.(viii) The coordinates of the point M.

Solution:
From the above figure,
(i)
The coordinates of point B is the distance of point B from x-axis and y-axis.
Therefore, the coordinates of point B are (–5, 2).
(ii)
The coordinates of point C is the distance of point C from x-axis and y-axis.
Therefore, the coordinates of point C are (5, –5).
(iii)
The point that represents the coordinates (–3, –5) is E.
(iv)
The point that represents the coordinates (2, –4) is G.
(v)
The abscissa of point D is the distance of point D from the y-axis. Therefore, the abscissa of point D is 6.

(vi)
The ordinate of point H is the distance of point H from the x-axis. Therefore, the abscissa of point H is –3.

(vii)
The coordinates of point L in the above figure is the distance of point L from x-axis and yaxis. Therefore, the coordinates of point L are (0, 5).
(viii)
The coordinates of point M in the above figure is the distance of point M from x-axis and yaxis. Therefore the coordinates of point M are (–3, 0).

## NCERT Solutions for Class 9 Maths Chapter 3 Coordinate Geometry : EX 3.3

#### Question 1:In which quadrant or on which axis do each of the points (–2, 4), (3, –1),(–1, 0), (1, 2) and (–3, –5) lie? Verify your answer by locating them on theCartesian plane.

Solution:
To determine the quadrant or axis of the points (–2, 4), (3, –1), (–1, 0), (1, 2) and
(–3, –5).
Plot the points (–2, 4), (3, –1), (–1, 0), (1, 2) and (–3, –5) on the graph.

From the figure, we can conclude that the points,
Point (–2, 4) lie in IInd quadrant.
Point (3, –1) lie in IVth quadrant.
Point (–1, 0) lie on the negative x-axis.
Point (1, 2) lie in Ist quadrant.
Point (–3, –5) lie in IIIrd quadrant.

#### Question 2:Plot the points (x, y) given in the following table on the plane, choosingsuitable units of distance on the axes.

Solution:

Draw X’OX and Y’OY as the coordinate axes and mark their point of intersection O as the Origin (0, 0).
In order to plot the table provided above,
Point A (–2, 8) – Take 2 units on OX’ and then 8 units parallel to OY.
Point B (–1, 7) – Take -1 unit on OX’ and then 7 units parallel to OY
Point C (0, –1.25) – Take 1.25 units below x-axis on OY’ on the y-axis
Point D (1, 3) – Take 1 unit on OX and then 3 units parallel to OY
Point E (3, –1) – Take 3 units on OX and then move 1 unit parallel to OY