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NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers by Swiflearn are by far the best and most reliable NCERT Solutions that you can find on the internet. These NCERT Solutions for Class 6 Maths Chapter 2 are designed as per the CBSE Class 6 Maths Syllabus. These NCERT Solutions will surely make your learning convenient & fun. Students can also Download FREE PDF of NCERT Solutions Class 6 Chapter 2. NCERT Solutions for Class 6 Maths Chapter 2: Whole Numbers Ex 2.1

Question 1:Write the next three natural numbers after 10999.

Solution:
Natural numbers are all the positive numbers without zero. So, to take out the next three numbers we will add 1 to the number.
10999 + 1 =11000
11000 +1 =11001
11001+ 1 =11002

Question 2:Write the three whole numbers occurring just before 10001.

Solution:
Whole numbers are natural numbers with 0. So, to find out the numbers which have occurred before, we will subtract 1 from the number,
10001 –1 =10000
10000 –1= 9999
9999 –1= 9998

Question 3:Which is the smallest whole number?

Solution 3:
The smallest whole number is 0.

Question 4:How many whole numbers are there between 32 and 53?

Solution:
Whole numbers are natural numbers with 0. So, all the numbers between 32 and 53 are whole numbers.
53 – 32- 1 =20  
There are 20 whole numbers between 32 and 53.

(c) 1099999(d) 2345670

Solution:
To find the successor of any number we add 1 to find the number.
a 2440701 +1 =2440702
b 100199+ 1= 100200
c 1099999+ 1= 1100000
d 2345670+ 1= 2345671

Question 6:Write the predecessor of:(a) 94(b) 10000(c) 208090(d) 7654321

Solution:
We know that to find the predecessor of any number we will subtract 1 from that number.
a 94 –1= 93
b 10000 –1 =9999
c 208090 –1 =208089
d 7654321 –1 =7654320

Question 7:In each of the following pairs of numbers, state which whole number is onthe left of the other number on the number line? Also write them with theappropriate sign (>, <) between them.(a) 530, 503(b) 370, 307(c) 98765, 56789(d) 9830415, 10023001

Solution:
(a) 530 > 503;

503 appears to be on the left side of the line and 530 appears to be on the right side of the line.

(b) 370 > 307;

307 appears to be on the left side of the line and 370 on the right side of the line.

(c) 98765 > 56789;

56789 is on the left side of the line and 98765 is on the right side of the line.

(d) 9830415 < 10023001;

9830415 is on the left side of the line and 10023001 is on the right side of the line

Solution:
(a) F
(b) F
(c) T
(d) T
(e) T
(f) F
(g) F
(h) F
(i) T
(j) F
(k) F
(l) T
(m)F

NCERT Solutions for Class 6 Maths Chapter 2: Whole Numbers Ex 2.2

Question 1:Find the sum by suitable rearrangement:(a) 837 + 208 + 363(b) 1962 + 453 + 1538 + 647

Solution:  Question 2:Find the product by suitable arrangement:(a) 2 × 1768 × 50(b) 4 × 166 × 25(c) 8 × 291 × 125(d) 625 × 279 × 16(e) 285 × 5 × 60(f) 125 × 40 × 8 × 25

Solution:     Question 3:Find the value of the following:(a) 297 × 17 + 297 × 3(b) 54279 × 92 + 8 × 54279(c) 81265 × 169 – 81265 × 69(d) 3845 × 5 × 782 + 769 × 25 × 218

Solution:    (a) 738 × 103(b) 854 × 102(c) 258 × 1008(d) 1005 × 168x

Solution:    Question 5:A taxi-driver filled his car petrol tank with 40 litres of petrol on Monday.The next day, he filled the tank with 50 litres of petrol. If the petrol costs ₹44 per litre, how much did he spend in all on petrol?

Solution:
On the first day he filled 40 litres and on the next day 50 litres, so
Total petrol filled in the car is 40 + 50 = 90
Price of 1 litre of petrol = ₹ 44
Thus, price of 90 litres of petrol, The total money spent on petrol was ₹ 3960

Question 6:A vendor supplies 32 litres of milk to a hotel in a morning, and 68 litres ofmilk in the evening. If the milk costs ₹ 15 per litre, how much money is dueto the vendor per day?

Solution:
The milk supplied during the morning time is 32 litres and in the evening time it is 68 litres,
Total amount of milk supplied = 68 + 32 = 100
Cost of 1 litre of milk = ₹ 15.
Total cost = ₹ 1500 is due to the vendor per day.

Solution:
(i) – (c)
(ii) – (a)
(iii) – (b)

NCERT Solutions for Class 6 Maths Chapter 2: Whole Numbers Ex 2.3 Solution: Question 2:If the product of two whole numbers is zero, can we say that one or both ofthem will be zero? Justify through examples.

Solution:
We know that, multiplying any number with 0 gives us 0, so we can say that one or both of the numbers are zero.
Example: – 99 × 0 = 0

Question 3:If the product of two whole number is 1, can we say that one or both ofthem will be 1? Justify through examples.

Solution:
We know that, multiplying any number with 1 will give the number itself so, it is only possible when both the numbers are 1.
Example: – 1 × 1 = 1, 1 × 4 = 4

(a) 728 × 101(b) 5437 × 1001(c) 824 × 25(d) 4275 × 125(e) 504 × 35

Solution     Write the next two steps. Can you say how the pattern works?

Solution:

After studying the pattern in the question, the next two steps are,
123456 x 8 + 6 = 987654
1234567 x 8 + 7 = 9876543

The pattern is:
1 x 8 + 1 = 9
12 x 8 + 2 = 98
123 x 8 + 3 = 987
1234 x 8 + 4 = 9876
12345 x 8 + 5 = 98765
123456 x 8 + 6 = 987654
1234567 x 8 + 7 = 9876543 